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tin Hollow Section
Weight Calculation
How is the weight of tin Hollow Section calculated?
Hollow section weight is the outer cross-section minus the hollow core: (height × width − (height − 2 × wall) × (width − 2 × wall)) × length × density. One metre of 40 × 40 × 3 mm tin Hollow Section weighs about 3.241 kg.
What is the density of tin?
The density of tin is taken as 7.3 g/cm³ (7,300 kg/m³).
tin Hollow Section weight table for standard sizes
| Size (mm) | Weight (kg/m) |
|---|---|
| 20 × 20 × 2 | 1.051 |
| 30 × 30 × 2 | 1.635 |
| 40 × 40 × 3 | 3.241 |
| 50 × 50 × 3 | 4.117 |
| 60 × 40 × 3 | 4.117 |
| 100 × 100 × 5 | 13.87 |
How accurate is the calculated weight?
Values are theoretical; production tolerances and corner radii can make the actual weight differ by 2–5%.